A reader recently suggested I write about modular arithmetic (aka “taking the remainder”). I hadn’t given it much thought, but realized the modulo is extremely powerful: it should be in our mental toolbox next to addition and multiplication.

Instead of hitting you in the face with formulas, let’s explore an idea we’ve been subtly exposed to for years. There’s a nice article on modular arithmetic that inspired this post.

## Odd, Even and Threeven

Shortly after discovering whole numbers (1, 2, 3, 4, 5…) we realized they fall into two groups:

- Even: divisible by 2 (0, 2, 4, 6..)
- Odd: not divisible by 2 (1, 3, 5, 7…)

Why’s this distinction important? It’s the beginning of abstraction — we’re noticing the *properties* of a number (like being even or odd) and not just the number itself (“37″).

This is huge — it lets us explore math at a deeper level and find relationships between *types* of numbers, not specific ones. For example, we can make rules like this:

- Even x Even = Even
- Odd x Odd = Odd
- Even x Odd = Even

These rules are general — they work at the property level. (Intuitively, I have a chemical analogy that “evenness” is a molecule some numbers have, and cannot be removed by multiplication.)

But even/odd is a very specific property: division by 2. What about the number 3? How about this:

- “Threeven” means a number is divisbile by 3 (0, 3, 6, 9…)
- “Throdd” means you are
*not*divisible by 3 (1, 2, 4, 5, 7, 8…)

Weird, but workable. You’ll notice a few things: there’s two types of throdd. A number like “4″ is 1 away from being threeven (remainder 1), while the number 5 is two away (remainder 2).

Being “threeven” is just another property of a number. Perhaps not as immediately useful as even/odd, but it’s there: we can make rules like “threeven x threeven = threeven” and so on.

But it’s getting crazy. We can’t make new words all the time.

## Enter the Modulo

The modulo operation (abbreviated “mod”, or “%” in many programming languages) is the remainder when dividing. For example, “5 mod 3 = 2″ which means 2 is the remainder when you divide 5 by 3.

Converting everyday terms to math, an “even number” is one where it’s “0 mod 2″ — that is, it has a remainder of 0 when divided by 2. An odd number is “1 mod 2″ (has remainder 1).

Why’s this cool? Well, our “odd/even” rules become this:

- Even x Even = 0 x 0 = 0 [even]
- Odd x Odd = 1 x 1 = 1 [odd]
- Even x Odd = 0 x 1 = 0 [even]

Cool, huh? Pretty easy to work out — we converted “properties” into actual equations and found some new facts.

What’s even x even x odd x odd? Well, it’s 0 x 0 x 1 x 1 = 0. In fact, you can see if there’s an even being multiplied _anywhere _the entire result is going to be zero… I mean even :).

## Clock Math

The sneaky thing about modular math is we’ve already been using it for keeping time — sometimes called “clock arithmetic”.

For example: it’s 7:00 (am/pm doesn’t matter). Where will the hour hand be in 7 hours?

Hrm. 7 + 7 = 14, but we can’t show “14:00″ on a clock. So it must be 2. We do this reasoning intuitively, and in math terms:

- (7 + 7) mod 12 = (14) mod 12 = 2 mod 12 [2 is the remainder when 14 is divided by 12]

The equation “14 mod 12 = 2 mod 12″ means, “14 o’clock” and “2 o’clock” look the same on a 12-hour clock. They are **congruent**, indicated by a triple-equals sign: 14 ≡ 2 mod 12.

Another example: it’s 8:00. Where will the big hand be in 25 hours?

Instead of adding 25 to 8, you might realize that 25 hours is just “1 day + 1 hour”. So, the clock will end up 1 hour ahead, at 9:00.

- (8 + 25) mod 12 ≡ (8) mod 12 + (25) mod 12 ≡ (8) mod 12 + (1) mod 12 ≡ 9 mod 12

You intuitively converted 25 to 1, and added that to 8.

## Fun Property: Math just works

Using clocks as an analogy, we can figure out whether the rules of modular arithmetic “just work” (they do).

**Addition/Subtraction**

Let’s say two times look the same on our clock (“2:00″ and “14:00″). If we add the same “x” hours to both, what happens?

Well, they change to the same amount on the clock! 2:00 + 5 hours ≡ 14:00 + 5 hours — both will show 7:00.

Why? Well, we never cared about the excess “12:00″ that the 14 was carrying around. We can just add 5 to the 2 remainder that both have, and they advance the same. For all congruent numbers (2 and 14), adding and subtracting has the same result.

**Multiplication**

It’s harder to see whether multiplication stays the same. If 14 ≡ 2 (mod 12), can we multiply both sides and get the same result?

Let’s see — what happens when we multiply by 3?

Well, 2:00 * 3 ≡ 6:00. But what’s “14:00″ * 3?

Remember, 14 = 12 + 2. So, we can say

- 14 * 3 = (12 + 2) * 3 = (12 * 3) + (2 * 3) mod 12

The first part (12 * 3) can be ignored! The “12 hour overflow” that 14 is carrying around just gets repeated a few times. But who cares? We ignore the overflow anyway.

When multiplying, it’s only the remainder that matters, which is the same 2 hours for 14:00 and 2:00. Intuitively, this is how I see that multiplication doesn’t change relationships with modular math (you can multiply both sides of a modular relationship and get the same result). See the above link for more rigorous proofs — these are my intuitive pencil lines.

## Uses Of Modular Arithmetic

Now the fun part — why is modular arithmetic useful?

**Simple time calculations**

We do this intuitively, but it’s nice to give it a name. You have a flight arriving at 3pm. It’s getting delayed 14 hours. What time will it land?

Well, 14 ≡ 2 mod 12. So I think of it as “2 hours and an am/pm switch”, so I know it will be “3 + 2 = 5am”.

This is a bit more involved than a plain modulo operator, but the principle is the same.

**Putting Items In Random Groups**

Suppose you have people who bought movie tickets, with a confirmation number. You want to divide them into 2 groups.

What do you do? “Odds over here, evens over there”. You don’t need to know how many tickets were issued (first half, second half), everyone can figure out their group instantly (without contacting a central authority), and the scheme works as more people buy tickets.

Need 3 groups? Divide by 3 and take the remainder (aka mod 3). You’ll have groups “0″, “1″ and “2″.

In programming, taking the modulo is how you can fit items into a hash table: if your table has N entries, convert the item key to a number, do mod N, and put the item in that bucket (perhaps keeping a linked list there). As your hash table grows in size, you can recompute the modulo for the keys.

**Picking A Random Item**

I use the modulo in real life. Really. We have 4 people playing a game and need to pick someone to go first. *Play the mod N mini-game!* Give people numbers 0, 1, 2, and 3.

Now everyone goes “one, two, three, shoot!” and puts out a random number of fingers. Add them up and divide by 4 — whoever gets the remainder exactly goes first. (For example: if the sum of fingers is 11, whoever had “3″ gets to go first, since 11 mod 4 = 3).

It’s fast and it works.

**Running Tasks On A Cycle**

Suppose tasks need to happen on a certain schedule:

- Task A runs 3x/hour
- Task B runs 6x/hour
- Task C runs 1x/hour

How do you store this information and make a schedule? One way:

- Have a timer running every minute (keep track of the minute as “n”)
- 3x / hour means once every 60/3 = 20 minutes. So task A runs whenever “n % 20 == 0″
- Task B runs whenever “n % 10 == 0″
- Task C runs whenever “n % 60 == 0″

Oh, you need task C1 which runs 1x per hour, but not the same time as task C? Sure, have it run when “n mod 60 == 1″ (still once per hour, but not the same as C1).

Mentally I see a cycle I want to “hit” at various intervals, so I insert a mod. The neat thing is that the hits can overlap independently. It’s a bit like XOR in that regard (each XOR can be layered — but that’s another article!).

Similarly, when programming you can print every 100th log item by doing: if (n % 100 == 0){ print… }.

It’s a very flexible, simple way to have items run on a schedule. In fact, it’s the way to answer the FizzBuzz sanity check. If you don’t have the modulo operation in your batbelt the question becomes much more tricky.

**Finding Properties Of Numbers**

Suppose I told you this:

- a = (47 * 2 * 3)

What can you deduce quickly? Well, “a” must be even, since it’s equal to something which involves multiplication by 2.

If I also told you:

- a = (39 * 7)

You’d balk. Not because you “know” the two products are different, but because one is clearly even, and the other is odd. There’s a problem: a can’t be the same number in both since the *properties don’t match up*.

Things like “even”, “threeven” and “mod n” are properties that are more general than individual numbers, and which we can check for consistency. So we can use modulo to figure out whether numbers are consistent, without knowing what they are!

If I tell you this:

- 3a + 5b = 8
- 3a + b = 2

Can these equations be solved with the integers? Let’s see:

- 3a + 5b = 8… let’s “mod 3 it”: 0 + 2b ≡ 2 mod 3, or b ≡ 1 mod 3
- 3a + b = 2… let’s “mod 3 it”: 0 + b ≡ 2 mod 3), or b ≡ 2 mod 3

A contradication, good fellows! B can’t be both “1 mod 3″ and “2 mod 3″ — it’s as absurd as being even and odd at the same time!

But there’s one gotcha: numbers like “1.5″ are neither even nor odd — they aren’t integers! The modular properties apply to integers, so what we can say is that b cannot be an *integer*.

Because, in fact, we can solve that equation:

- (3a + 5b) – (3a +b) = 8 – 2
- 4b = 6
- b = 1.5
- 3a + 1.5 = 2, so 3a = 0.5, and a = 1/6

Don’t get seduced by the power of modulo! Know its limits: it applies to integers.

**Cryptography**

Playing with numbers has very important uses in cryptography. It’s too much to cover here, but modulo is used in Diffie-Hellman Key Exchange — used in setting up SSL connections to encrypt web traffic.

**Plain English**

Geeks love to use technical words in regular contexts. You might hear “X is the same as Y modulo Z” which means roughly “Ignoring Z, X and Y are the same.”

For example:

- b and B are identical, modulo capitalization
- The iTouch and iPad are identical, modulo size

## Onward and Upward

It’s strange thinking about the “utility” of the modulo operator — it’s like someone asking why exponents are useful. In everyday life, not very, but it’s a tool to understand patterns in the world, and create your own.

In general, I see a few general use cases:

- Range reducer: take an input, mod N, and you have a number from 0 to N-1.
- Group assigner: take an input, mod N, and you have it tagged as a group from 0 to N-1. This group can be agreed upon by any number of parties — for example, different servers that know N = 20 can agree what group ID=57 belongs to.
- Property deducer: treat numbers according to properties (even, threeven, and so on) and work out principles derived at the property level

I’m sure there’s dozens more uses I’ve missed — feel free to comment below. Happy math!

I love this series; it reminds me of everything I’ve forgotten since school.

I think there’s a small error in this entry, though: on clocks, the big hand is usually the minute hand; thus, “in 7 hours”, the big hand will be in exactly the same place it is now. The *small* hand, though, will have moved.

@Robert: *slaps forehead*, thank you for that catch! Rather than trying to be clever, I think I’ll just say “hour hand” :).

“3a + 5b = 7… let’s “mod 3 it”: 0 + 2b ≡ 2 mod 3, or b ≡ 1 mod 3″

Shouldn’t it be “0 + 2b = 1″ since 7 mod 3 1?

@Mark: Thank you! Another case of me being too clever for my own good… it should be 3a + 5b = 8 to make that equation work. I’ll update the article.

Good post!

In addition to public-key cryptography like Diffie Hellman and RSA, modular operations are very useful in private-key (symmetric-key) algorithms like the Advanced Encryption Standard (AES).

Modular operations are useful there because you can represent a byte as a polynomial with coefficients that are either 1 or 0. Once you do this, you can take advantage of a lot of nice mathematical properties. Instead of dividing by a number, you can divide by a polynomial and things just work out. Logarithms work in a similar way.

I had fun learning about the details and wrote about the details in Act 3 of my stick figure guide to AES.

The modulo operation (abbreviated “mod”, or “%” in many programming languages) is the remainder when dividing. For example, ”5 mod 3 = 2″ which means 2 is the remainder when you divide 5 by 3.This is what I used to think too, but it’s wrong. It only works this way if both numbers are positive. When either of the numbers is negative, it doesn’t quite work that way.

5 mod 3 = 2

However

-5 mod 3 = 1

That’s because the real definition is that a mod n = b if (a – b) is an integer multiple of n.

5 – 2 = 3 => 5 mod 3 = 2.

(-5) – 1 = 6 = 2 * 3 => -5 mod 3 = 1

This is confusing enough, but the modulo operator in programming languages has behavior that is hard to predict for negative values. (Notice that that article also states, incorrectly, that modulo is the same as remainder.)

If you end up writing an article about negative mods, I would use the “clock math” basis for it. In a problem like a mod n = b, the n is the number of places on the clock. The a is the number of steps you take, with negative being backwards. b is the number you land on.

It’s also possible to have a negative n, but I don’t know what that’s supposed to mean…maybe the clock is made of anti-matter?

‘Intuitively, I have a chemical analogy that “evenness” is a molecule some numbers have, and cannot be removed by multiplication.’

How about a genetic analogy? Let’s say that being even is a dominant allele, and being odd is recessive. Whenever a multiplication has at least one dominant allele, the result is even. Only when both multiplicands are odd, is the result odd.

@Yuval: Oh, that’s an interesting analogy too — thanks! :).

a = b (mod n) since the equal sign is often easier to type than the congruent sign that was intended.

Basically, the truth of a = b (mod n) is the same as the truth of mod(a,n) = mod(b,n)

Can anyone answer this question and explain it?

In mod 6, What is 3 divided by 5??

3x^3-16x-1≡AX(x-1)(x+2)+B(x-1)^2+C(4x^2+3)

Jess, I think I can answer your question. If you want to take 3/5 (mod 6), you just need to rephrase the question a bit. What do we want 3/5 to do? Basically, the answer to “3 divided by 5,” which we often call “three fifths,” has the defining property that if you multiply it by 5 you get 3. So instead of finding 3/5 (mod 6), I’ll find the number that has the property that when I multiply it by 5 (mod 6) I get 3.

What number is this? 3 seems to fit the bill, since 3*5 = 15 = 3 (mod 6). Hence, 3/5 = 3 (mod 6).

There’s another way to understand this in this case only. Since 5 = -1 (mod 6), your question is the same as 3/(-1) (mod 6), which is clearly -3, which is the same as 3 (mod 6).

Hope that helps.

@Dan: Awesome answer, thanks for dropping by!

Brilliant! This article explains everything really clearly and I totally understand mods now!!!!

Thx!!!!!

so……….like this?

Find the last digit of 3 to the power of 152.

First we make a chart:

3 to the 1= 3 mod 10.

3 to the 2= 9 mod 10.

3 to the 3= 7 mod 10.

3 to the 4= 1 mod 10.

3 to the 5= 3 mod 10.

9

7

1

We find a pattern of 4 numbers (3, 9, 7, 1) so we divide 152 by 4. It divides in evenly so 1 (the fourth number in the pattern) is the last digit of 3 to the power of 152.

Thanks!

In what modular arithmetics would be true? 1-3=2

Thanks

@ Bob 1 mod 4 – 3 mod 4 = -2 mod 4 = 2 mod 4

Good article, there is just a small mistake :

“The modular properties apply to integers, so what we can say is that b cannot be an integer.”

Actually, b could be an integer if a wasn’t an integer.

For exemple take :

3a+5b=6

3a+4b=2

taking mod 3 you have :

2b=0 mod 3 ie b=0 mod 3

b=2 mod 3

According to you that would mean b isn’t an integer.

Except the solution of this system is a=-14/3 and b=4.

All you can deduce from this contradiction ( that b=0 mod 3 and b=2 mod 3 ) is that a and b aren’t both integer.

what a nice page.. i love it,, thanks a lot ..it fascinates me about the power of modulo,,, and that,s why ..I’m gonna make a study on that…thanks..

@Joann: Thanks!

Is there a good book you could recommend for starting out with modular arithmetic?

Thanks

Thank you so much ^_^

@Ingrid: You’re welcome!

LOL thanks

I loved this article , it’s interesting and I really wasn’t know where we apply the modular arithmetic in our daily life..Thank you very very much:)))))

@Math student: Thanks for the note, glad you enjoyed it!

Hi,

I recently saw the following video:

http://www.youtube.com/watch?feature=player_embedded&v=3QnD2c4Xovk

In which at 4min and 35seconds, following math-e-magic happens:

16^54 mod 17

becomes (I get this part)

((3^24 mod 17)^54) mod 17

becomes

3^(24*54) mod 17 (I did not get this part)

Can I request you to please explain the last conversion?

Thank you for your time!

Very Good Illustration

So, why can’t we say that 5.5==2.5 mod 3?

As always, great article! I remember the feeling I got when I finally had the Chinese Remainder Theorem explained to me (over IRC), including getting the meshing mod equations together and multiplicative inverse part.

@David: You were so close to the answer of your question! if you would just resort to paper and pencil and using the clock math you yourself explained nicely :

for a negative n you simply mark the clock anti clockwise with negative numbers, of course the marking of the zero at top of the clock stays the same. The rest of the procedure is the same as widely known. If you want to know the remainder of a positive integer you move clockwise a number of steps equal to that number.Else if you have a negative number that you want to know the reminder of, you move Anticlockwise. In both cases the marking you land on is your answer. As you see the clock math is the best analogy to visualize the modular math whatever the sign of the integers involved.

how can this be solved 2x+3y=13,2x-y=1

how can this be solved 2x+3y=13(mod 5),2x-y=1(mod 5)

how to take addition of modulo 2^32

your work is very comprehensive.please keep it up

any body workout this problem and send me the reply

%8(remainder 8 without using any arithmetic operations like add,sub,div,multi)

send me the solution as early as possible