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	<title>
	Comments on: How to Add 1 through 100 using Calculus	</title>
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	<link>https://betterexplained.com/articles/how-to-add-1-to-100-using-calculus/</link>
	<description>Math lessons that click</description>
	<lastBuildDate>Wed, 27 Dec 2017 20:08:08 +0000</lastBuildDate>
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		<title>
		By: Matt		</title>
		<link>https://betterexplained.com/articles/how-to-add-1-to-100-using-calculus/#comment-336297</link>

		<dc:creator><![CDATA[Matt]]></dc:creator>
		<pubDate>Wed, 27 Dec 2017 20:08:08 +0000</pubDate>
		<guid isPermaLink="false">https://betterexplained.com/?p=10127#comment-336297</guid>

					<description><![CDATA[&lt;p&gt;I not too long ago thought about this exact same problem, oddly enough.  Instead of integrating on the top-right point on each rectangle-bar, integrate on the top-middle point of each rectangle-bar.&lt;/p&gt;&lt;p&gt;To &quot;fix&quot; the integral, instead of integrating x from 0 to x, you integrate from 0.5 to n + 0.5, and you get the mid-point of each bar.  In doing some more work, it turns out you can get the exact answer using an integral (and probably an even nicer way to derive the formula for 1 + 2 + 3 + ... + n).  For this, you simply integrate x from 0.5 to n + 0.5, and you get the formula (n)(n+1)/2.&lt;/p&gt;&lt;p&gt;Going beyond this seems to be trickier.  The formula is 1^2 + 2^2 + 3^2 + ... = (1/3)n^3 + (1/2)n^2 + (1/6)n.  If I have the integral from 0.5 to n + 0.5 of x^2 - 1/12, I get the formula.  I tested it on the case of n = 5 and got 55 both ways.&lt;/p&gt;]]></description>
			<content:encoded><![CDATA[<p>I not too long ago thought about this exact same problem, oddly enough.  Instead of integrating on the top-right point on each rectangle-bar, integrate on the top-middle point of each rectangle-bar.</p>
<p>To "fix" the integral, instead of integrating x from 0 to x, you integrate from 0.5 to n + 0.5, and you get the mid-point of each bar.  In doing some more work, it turns out you can get the exact answer using an integral (and probably an even nicer way to derive the formula for 1 + 2 + 3 + ... + n).  For this, you simply integrate x from 0.5 to n + 0.5, and you get the formula (n)(n+1)/2.</p>
<p>Going beyond this seems to be trickier.  The formula is 1^2 + 2^2 + 3^2 + ... = (1/3)n^3 + (1/2)n^2 + (1/6)n.  If I have the integral from 0.5 to n + 0.5 of x^2 - 1/12, I get the formula.  I tested it on the case of n = 5 and got 55 both ways.</p>
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	<item>
		<title>
		By: kalid		</title>
		<link>https://betterexplained.com/articles/how-to-add-1-to-100-using-calculus/#comment-334717</link>

		<dc:creator><![CDATA[kalid]]></dc:creator>
		<pubDate>Mon, 20 Mar 2017 19:24:05 +0000</pubDate>
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					<description><![CDATA[In reply to &lt;a href=&quot;https://betterexplained.com/articles/how-to-add-1-to-100-using-calculus/#comment-334716&quot;&gt;Diana&lt;/a&gt;.

&lt;p&gt;Thanks Diana, hope it helps them!&lt;/p&gt;]]></description>
			<content:encoded><![CDATA[<p>In reply to <a href="https://betterexplained.com/articles/how-to-add-1-to-100-using-calculus/#comment-334716">Diana</a>.</p>
<p>Thanks Diana, hope it helps them!</p>
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	<item>
		<title>
		By: Diana		</title>
		<link>https://betterexplained.com/articles/how-to-add-1-to-100-using-calculus/#comment-334716</link>

		<dc:creator><![CDATA[Diana]]></dc:creator>
		<pubDate>Mon, 20 Mar 2017 18:22:21 +0000</pubDate>
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					<description><![CDATA[&lt;p&gt;Thx Khalid... give me some ideas to explain integral in a more interesting way to my students&lt;/p&gt;]]></description>
			<content:encoded><![CDATA[<p>Thx Khalid... give me some ideas to explain integral in a more interesting way to my students</p>
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			</item>
	<item>
		<title>
		By: kalid		</title>
		<link>https://betterexplained.com/articles/how-to-add-1-to-100-using-calculus/#comment-334707</link>

		<dc:creator><![CDATA[kalid]]></dc:creator>
		<pubDate>Sun, 19 Mar 2017 03:43:42 +0000</pubDate>
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					<description><![CDATA[In reply to &lt;a href=&quot;https://betterexplained.com/articles/how-to-add-1-to-100-using-calculus/#comment-334702&quot;&gt;Rodolfo&lt;/a&gt;.

&lt;p&gt;Neat extension! We can account for the extra area by making the sum a bit larger.&lt;/p&gt;]]></description>
			<content:encoded><![CDATA[<p>In reply to <a href="https://betterexplained.com/articles/how-to-add-1-to-100-using-calculus/#comment-334702">Rodolfo</a>.</p>
<p>Neat extension! We can account for the extra area by making the sum a bit larger.</p>
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