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	<title>
	Comments on: Learning Tip: The 5 Second Gutcheck	</title>
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	<description>Math lessons that click</description>
	<lastBuildDate>Wed, 03 Oct 2018 04:37:00 +0000</lastBuildDate>
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		<title>
		By: kalid		</title>
		<link>https://betterexplained.com/articles/gutcheck/#comment-351220</link>

		<dc:creator><![CDATA[kalid]]></dc:creator>
		<pubDate>Wed, 03 Oct 2018 04:37:00 +0000</pubDate>
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					<description><![CDATA[In reply to &lt;a href=&quot;https://betterexplained.com/articles/gutcheck/#comment-351186&quot;&gt;Bradley Kuszmaul&lt;/a&gt;.

&lt;p&gt;Great point -- another nice opportunity for a gutcheck (All the options lie on the real number line).&lt;/p&gt;]]></description>
			<content:encoded><![CDATA[<p>In reply to <a href="https://betterexplained.com/articles/gutcheck/#comment-351186">Bradley Kuszmaul</a>.</p>
<p>Great point -- another nice opportunity for a gutcheck (All the options lie on the real number line).</p>
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		<title>
		By: Bradley Kuszmaul		</title>
		<link>https://betterexplained.com/articles/gutcheck/#comment-351186</link>

		<dc:creator><![CDATA[Bradley Kuszmaul]]></dc:creator>
		<pubDate>Tue, 02 Oct 2018 19:03:00 +0000</pubDate>
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					<description><![CDATA[&lt;p&gt;i^i has many solutions.    Since i=e^{i (pi/2 + 2pi k)} for any integer k, we have i^i = e^{-pi/2 + 2pi k} for any integer k.   So it could be a very small number or a very large number.&lt;/p&gt;]]></description>
			<content:encoded><![CDATA[<p>i^i has many solutions.    Since i=e^{i (pi/2 + 2pi k)} for any integer k, we have i^i = e^{-pi/2 + 2pi k} for any integer k.   So it could be a very small number or a very large number.</p>
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